Which statement is true about Kp?

Study for the DAT Bootcamp General Chemistry Test. Enhance your skills with detailed questions and explanations. Master exam topics such as atomic structure, chemical reactions, and periodic trends. Prepare confidently for your exam!

Multiple Choice

Which statement is true about Kp?

Explanation:
Kp represents the equilibrium constant written in terms of the partial pressures of gases. In gas-phase equilibria, the activities of the species are related to their partial pressures, so the equilibrium expression uses p for products raised to their stoichiometric powers divided by the same for reactants. This is different from Kc, which uses concentrations instead of pressures. The two are connected by Kp = Kc (RT)^{Δn}, where Δn is the change in the number of moles of gas. Temperature matters because changing temperature shifts the position of equilibrium, altering the value of Kp (and Kc) accordingly. It isn’t a rate constant, and it isn’t independent of temperature.

Kp represents the equilibrium constant written in terms of the partial pressures of gases. In gas-phase equilibria, the activities of the species are related to their partial pressures, so the equilibrium expression uses p for products raised to their stoichiometric powers divided by the same for reactants. This is different from Kc, which uses concentrations instead of pressures. The two are connected by Kp = Kc (RT)^{Δn}, where Δn is the change in the number of moles of gas. Temperature matters because changing temperature shifts the position of equilibrium, altering the value of Kp (and Kc) accordingly. It isn’t a rate constant, and it isn’t independent of temperature.

Subscribe

Get the latest from Examzify

You can unsubscribe at any time. Read our privacy policy